Write a C program.
Standard library defines alibrary function atoi. This function converts an array of digit characters, which represents a decimal integer literal, into the
corresponding decimal integer. For example, given a char array (string) of “134”, atoi returns an integer 134.Implement your version of atoi called
my_atoi, which does exactly the same thing.
Your program keeps on reading from the user until “quit” is entered.
A more intuitive approach, which you should implement here, is to calculate by traversing the array from right to left and convert following the traditional concept of …. 10^310^210^110^0
Sampleinput/output
Enter a word of positive number or ‘quit’: 12
12 (014, 0XC)24 144
Enter a word of positive number or ‘quit’: 100
100 (0144, 0X64)200 10000
Enter a word of positive number or ‘quit’:quit
INCOMPLETE CODE
#include <stdio.h>
#include <string.h> /* for strcpy() */
#include <math.h> /* for pow() */
int my_atoi (char c[]); /* function declaration */
int main(){
int a;
char arr [10];
char argu [10];
printf(“Enter a postive number or ‘quit’: ” );
scanf(“%s”, arr);
while( )
{
strcpy(argu, arr);
a = my_atoi(argu);
printf(“%d (%#o, %#X)t%dt%.0fn”, a, a, a, a*2, pow(a,2));
/* read again */
printf(“Enter a postive number or ‘quit’: ” );
scanf(“%s”, arr);
}
return 0;
}
/* convert an array of digit characters into a decimal int */
/*
Here you should scan from right to left. This is a little complicated but more straightforward */
int my_atoi (char c[])
{
}
