(Solved Homework): 4.   Find   Longest   Repeated   Pattern                  public   int   findLongest(char   c,   String   s,   int   length)     

4.   Find   Longest   Repeated   Pattern
public   int   findLongest(char   c,   String   s,   int   length)

Given   a   String,   find   the   longest   sequence   of   matching   characters   in   that   String   and   return   that   int   length.   For   instance,   “aaabbccccccdde”   has   6   c’s   so   the   method   would   return   6       Call   this   method   passing   it   the   first   character   in   the   String,   the   rest   of   the   String   and   1,   as   in       findLongest(‘a’,       s,   1)       length   represents   the   longest   matching   sequence   found   so   far,   which   is   1   because   we   found   ‘a’   Base   case:   if   length==0   or   length==1   return   the   length   of   s       Recursive   cases:   if   c   matches   the   0th   character   of   s,   then   we   extend   the   sequence,       return   the   value   of   the   recursive   call   with   c,   the   rest   of   s   after   the   0th   character,   and
length+1       else   no   match,   return   whichever   is   larger,   length   (the   length   we   found   of   char   c   up   to   this   point   in   s),   or   the   value   returned   by   recursively   calling   the   method   with   the   0th   character   of   s,   the   rest   of   s,   and   1   as   we   are   starting   over
Example:   “aaabbccccccdde”       Call   the   method   with   ‘a’,   “aabbccccccdde”,   1       First   character   matches,   so   call   with   ‘a’,   “abbccccccdde”,   2       First   character   matches,   so   call   with   ‘a’,   “bbccccccdde,   3       No   match,   so   return   max(3,   call   with   ‘b’,   “bccccccdde”,   1)       First   character   matches,   so   call   with   ‘b’,   “ccccccdde,   2       No   match,   so   return   max(2,   call   with   ‘c’,   “cccccdde”,   1)       First   character   matches,   so   call   with   ‘c’,   “ccccdde”,   2       …       Eventually   these   calls   return   6   (6   c’s   found)       Return   max(2,   6)       Return   max(3,   6)
Run   your   program   on   the   following   inputs.           “aabbbcddddddeefffghiii”,   “19855aa00000cc24443bbb”   ,   “33335557i322k555554p”,   “2oo88rrrrr55ttyuuuuuuuuuuuuuuu44uuuuuuuuu4u444uuuuuuuuuuuuuuu”

This is what I have so far…

public static int findLongest(char c, String s, int length){
if (s.charAt(0) == s.charAt(1)) {
s = s.substring(1);
length ++;
System.out.println(s + length);
findLongest(c, s, length);
else if (s.charAt(0) != s.charAt(1)){
s = s.substring(1);
length = 1;
System.out.println(s + ” ” + length);
findLongest(c, s, length);
return length;

Thanks for any help!!

Expert Answer

 //program saved as FrequentCharacter.java

import java.util.Scanner;

public class FrequentCharacter {

public static void main(String[] args) {

//if you want to read the string from user use the below lines
/*Scanner input=new Scanner(System.in);
String srt1;
System.out.print(“nEnter a string: “);

String str1=”apple banana orange”;
char ch=’ ‘;
int i=0;
boolean found=false;

//run a loop until a nonrepeating character is found
int charcount=0;
//get each char at a time
//get character count by using countChar method
charcount=countChar(str1,ch );
//if charcount is 1 then set found=true
i++;//increment count

//display output
System.out.println(“First nonrepeating charater is ‘”+ch+”‘”);

//function that return the count of a character in a string
public static int countChar(String s,char c)
int count=0;
//loop through each character in the string and compare with c
for(int i=0;i<s.length();i++)
//if match found increment count
//return count
return count;




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