(Homework Solution): Write a program with a language of your choice that produces a truth table for the

I am trying to write a program to solve this problem for discrete math. I am trying to code the program in Java. We need to produce a truth table. One of the restrictions is that we are not allowed to use any logical operators in our functions. (&&, ||, !). Also, I want to make sure I print out “true” and “false” on the table. Not “1” and “0”. It looks like the table listed below.

Write a program with a language of your choice that produces a truth table for the following proposition: NOTE 1/ Your program must have the following functions: boolean implication( boolean p, boolean q) boolean or(boolean p, boolean q) boolean and(boolean p, boolean boolean biconditional(boolean p, boolean q) boolean negation(boolean p) q) 2/ Do not use || and && in your functions. 3/ Your program should use only six columns (one for each variable, and one for the given proposition.

Expert Answer

answers

I computed p->q as x1 r^t as x2 s'(negation s) as x3 x4 as x1<->x2 and result as

x4 v x3.

Solution:

public class TruthTable {

public static void main(String[] args) {

TruthTable tt=new TruthTable();

System.out.println(“Truth table for the expression isn”);

System.out.println(“ptqtrtstttexpression”);

boolean p,q,r,s,t,x1,x2,x3,x4,result;

int n;

int values[]=new int[6];

for(int i=0;i<32;i++)

{

n=i;

for(int j=0;j<5;j++)

{

values[j]=n%2;

n=n/2;

}

if(values[0]==0)

t=false;

else

t=true;

if(values[1]==0)

s=false;

else

s=true;

if(values[2]==0)

r=false;

else

r=true;

if(values[3]==0)

q=false;

else

q=true;

if(values[4]==0)

p=false;

else

p=true;

x1=tt.implication(p, q);

x2=tt.and(r, t);

x3=tt.negation(s);

x4=tt.biconditional(x1, x2);

result=tt.or(x4, x3);

System.out.println(p+”t”+q+”t”+r+”t”+s+”t”+t+”t”+result);

}

boolean implication(boolean p,boolean q)

{

if(p==false)

{

return true;

}

else

{

if(q==true)

return true;

else

return false;

}

boolean or(boolean p,boolean q)

{

if(p==true)

return true;

else

{

if(q==true)

return true;

else

return false;

}

boolean and(boolean p,boolean q)

{

if(p==false)

return false;

else

{

if(q==true)

return true;

else

return false;

}

boolean biconditional(boolean p,boolean q)

{

if(p==true)

{

if(q==true)

return true;

else

return false;

}

else

{

if(q==false)

return true;

else

return false;

}

boolean negation(boolean p)

{

if(p==true)

return false;

else

return true;

}

Output:

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