# (Homework Solution): Question: A) Modify the distance-vector-routing pseudo-code such that each pair of neighboring nodes (p, q)…

a) Modify the distance-vector-routing pseudo-code such that each pair of neighboring nodes (p, q) has a cost for the directed edge (p, q) and a cost for the directed edge (q, p). Furthermore, have each node remember the cost vector received by its neighbor, and take advantage of this new information that it maintains.

Code: declarations:

node p

inp

G    : set {g | g is a neighbor of p}

up   : array [G] of boolean, {is my neighbor up? or dead?}

var

rtb : array [NID] of G, {routing table}

cost : array [NID] of integer, {cost to reach each node}

d    : NID, {temporary variable}

c    : array [NID] of integer {temporary variable}

param

g: element of G {g can be any neighbor}

Code: actions (data):

begin

resp:

if d = p then skip {arrived}

else if d ¹ p Ù cost[d] < ¥ then
send data(d) to node rtb[d]

else if d ¹ p Ù cost[d] = ¥ then skip {non reachable}

end if

Code: send distance vector action, and detect down neighbors action:

event: true {at anytime, send cost to all neighbors}

resp:

if up[g] then send update(cost) to node g

end if

event: ~up[g] {has the neighbor died?}

resp:

for every d do

if rtb[d] = g then cost[d] = ¥

end if

end for

resp:   {compare costs to all destinations}

for every d do     {for every destination, compare c[] and cost[]}

if d = p then cost[p] := 0

end if

if d ¹ p Ù (rtb[d] = g Ú c[d] + 1 < cost[d])

then {change routing table to point to g for dest. d}

rtb[d] := g;

cost[d] := c[d]+1   {I assume link cost of 1 for simplicity}

end if

end for

end {code}

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