# (Homework Solution): Problem 3 Matrix 10 Points Create a 3×3 matrix of int values. Implement four functions,

Problem 3 Matrix 10 Points Create a 3×3 matrix of int values. Implement four functions, each expecting the matrix as parameter input. The first function must use a nested loop to prompt a user to enter each value Show the indices when prompting for input and populate the matrix with these values. The second function outputs the matrix and formats the output to align all columns and rows to accommodate values up to 1000. The third function finds and returns the minimum value in the matrix. The fourth function finds and returns the maximum value in the matrix. Call each function from the main and output the minimum and maximum values returned by the third and fourth function respectively. Input Value at 0,0: 7 Value at 0,1: 2

code:

#include <iostream>

#include <iomanip>

using namespace std;

for(int i=0;i<3;i++)

for(int j=0;j<3;j++){

cout << “value at “<< i << “,” << j << “:”;

cin >> matrix[i][j];

}

}

void printMatrix(int (&matrix)[3][3]){

//printing matrix

for(int i=0;i<3;i++){

cout << “[“;

for(int j=0;j<3;j++){

if(j<2)

cout << setw(4) << right << matrix[i][j] << “,”;

else

cout << setw(4) << right << matrix[i][j];

}

if(i<2)

cout << “],” << endl;

else

cout << “];” << endl;

}

}

int findMaximum(int (&matrix)[3][3]){

int max = -9999;

for(int i=0;i<3;i++)

for(int j=0;j<3;j++){

if(matrix[i][j] > max)

max = matrix[i][j];

}

return max;

}

int findMinimum(int (&matrix)[3][3]){

int min = 99999;

for(int i=0;i<3;i++)

for(int j=0;j<3;j++){

if(matrix[i][j] < min)

min = matrix[i][j];

}

return min;

}

int main()

{

int matrix[3][3];

printMatrix(matrix);

cout << “Maximum element in matrix : ” << findMaximum(matrix) <<endl;

cout << “Minimum element in matrix : ” << findMinimum(matrix) <<endl;

return 0;

}

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